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JEE Main 2026 (22 Jan, Shift 1) · Speed of EM Waves in a Medium

Speed of EM Waves in a Medium question from JEE Main 2026 (22 Jan, Shift 1)

Q4JEE Main 2026 · 22 JAN · SHIFT 1Medium

Speed of EM Waves in a Medium

The electric field of a plane electromagnetic wave, travelling in an unknown nonmagnetic medium is given by,

Ey=20sin⁡(3×106x−4.5×1014t) V/mE_y = 20 \sin\left(3 \times 10^{6} x - 4.5 \times 10^{14} t\right)\text{ V/m}

(where x,tx, t and other values have S.I. units). The dielectric constant of the medium is ______ (speed of light in free space is 3×108 m/s3 \times 10^{8}\text{ m/s})

Numerical answer type. Work it out, then open the answer.

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Answer: 4

  1. v=ω/k=4.5×10143×106=1.5×108v = \omega/k = \dfrac{4.5 \times 10^{14}}{3 \times 10^{6}} = 1.5 \times 10^{8} m/s
  2. n=c/v=2n = c/v = 2
  3. Non-magnetic: K=n2=4K = n^2 = 4
  4. So the answer is 4.
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