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NEET 2010 (AIPMT, Mains) · Nature of EM Waves & Wave Equation

Nature of EM Waves & Wave Equation question from NEET 2010 (AIPMT, Mains)

Q87NEET 2010 · AIPMT · MAINSMedium

Nature of EM Waves & Wave Equation

The electric field of an electromagnetic wave in free space is given by E⃗=10cos⁡(107t+kx)j^ V/m,\vec{E} = 10\cos(10^{7}t + kx)\hat{j}\text{ V/m}, where t and x are in seconds and metres respectively. It can be inferred that

(1) the wavelength λ\lambda is 188.4 m.

(2) the wave number k is 0.33 rad/m.

(3) the wave amplitude is 10 V/m.

(4) the wave is propagating along +x direction.

Which one of the following pairs of statements is correct?

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Answer: (d)

  1. ω=107\omega = 10^{7} rad/s, k=ω/c=1073×108=0.033k = \omega/c = \dfrac{10^{7}}{3\times10^{8}} = 0.033 rad/m, so (2) is false.
  2. λ=2π/k=2π×30=188.4\lambda = 2\pi/k = 2\pi\times30 = 188.4 m, so (1) is true.
  3. Amplitude =10= 10 V/m, so (3) is true; (ωt+kx)(\omega t + kx) means travel along −x-x, so (4) is false.
  4. So the answer is (d) (1) and (3).
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