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MHT CET 2026 (14 May, Shift 1) · Electric Flux & Gauss's Law

Electric Flux & Gauss's Law question from MHT CET 2026 (14 May, Shift 1)

Q3MHT CET 2026 · 14 MAY · SHIFT 1Easy

Electric Flux & Gauss's Law

The electric flux entering and leaving an enclosed surface are Φ1\Phi_1 and Φ2\Phi_2 respectively. The electric charge inside the surface will be (ε0\varepsilon_0 = permittivity of vacuum)

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Answer: (d)

  1. Net outward flux =Φ2−Φ1= \Phi_2 - \Phi_1 (leaving minus entering).
  2. Gauss's law: Φ2−Φ1=qε0⇒q=ε0(Φ2−Φ1)\Phi_2 - \Phi_1 = \dfrac{q}{\varepsilon_0} \Rightarrow q = \varepsilon_0(\Phi_2 - \Phi_1)
  3. So the answer is (d).
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