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JEE Main 2025 (23 Jan, Shift 1) · Electric Flux & Gauss's Law

Electric Flux & Gauss's Law question from JEE Main 2025 (23 Jan, Shift 1)

Q15JEE Main 2025 · 23 JAN · SHIFT 1Easy

Electric Flux & Gauss's Law

The electric flux is ϕ=ασ+βλ\phi = \alpha\sigma + \beta\lambda where λ\lambda and σ\sigma are linear and surface charge density, respectively. (αβ)\left(\frac{\alpha}{\beta}\right) represents

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Answer: (a)

  1. Both terms have the same dimensions: ασ=βλ\alpha\sigma = \beta\lambda dimensionally.
  2. αβ=λσ=C/mC/m2=m\dfrac{\alpha}{\beta} = \dfrac{\lambda}{\sigma} = \dfrac{\text{C/m}}{\text{C/m}^2} = \text{m}
  3. A length, so the answer is (a) displacement.
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