The electric potential at a point in free space due to charge Q coulomb is Q × 1011 volts. The electric field at that point is (a) 4πε₀ Q × 10²⁰ volt/m (b) 12 π 0Q × 1022 volt/m (c) 4πε₀ Q × 10²² volt/m (d) 12πε₀ Q × 10²⁰ volt/m

Answer: (c). V = (Q)/(4πε₀ r) = Q×10¹¹ ⇒ r = 14πε₀×10¹¹ E = V/r = Q×10¹¹×4πε₀×10¹¹ E = 4πε₀ Q×10²² V/m So the answer is (c).

The electric potential at a point in free space due to charge Q… | NEET 2008 (AIPMT)

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Electric Potential & Equipotentials

The electric potential at a point in free space due to charge Q coulomb is Q $\times$ 1011 volts. The electric field at that point is

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Answer: (c)

$V = \dfrac{Q}{4\pi\varepsilon_0 r} = Q\times10^{11} \Rightarrow r = \dfrac{1}{4\pi\varepsilon_0\times10^{11}}$
$E = \dfrac{V}{r} = Q\times10^{11}\times4\pi\varepsilon_0\times10^{11}$
$E = 4\pi\varepsilon_0 Q\times10^{22}$ V/m
So the answer is (c).