The electric potential at the center of two concentric half rings of radii R₁ and R₂, having same linear charge density λ is ( ε₀ = permittivity of free space) (a) 2λ/ε₀ (b) λ/2ε₀ (c) λ/4ε₀ (d) λ/ε₀

Answer: (b). Half ring: V = (k(λπ R))/(R) = (λ)/(4ε₀), independent of R. Potential is a scalar, so add both rings. V = (λ)/(4ε₀) + (λ)/(4ε₀) = (λ)/(2ε₀) So the answer is (b) λ/2ε₀.

The electric potential at the center of two concentric half rings of… | MHT CET 2026 (13 Apr, Shift 2)

Q11MHT CET 2026 · 13 APR · SHIFT 2Medium

Electric Potential & Equipotentials

The electric potential at the center of two concentric half rings of radii $R_1$ and $R_2$ , having same linear charge density $\lambda$ is ( $\epsilon_0$ = permittivity of free space)

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Answer: (b)

Half ring: $V = \dfrac{k(\lambda\pi R)}{R} = \dfrac{\lambda}{4\epsilon_0}$ , independent of $R$ .
Potential is a scalar, so add both rings.
$V = \dfrac{\lambda}{4\epsilon_0} + \dfrac{\lambda}{4\epsilon_0} = \dfrac{\lambda}{2\epsilon_0}$
So the answer is (b) $\lambda/2\epsilon_0$ .

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Electric Potential & Equipotentials question from MHT CET 2026 (13 Apr, Shift 2)

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