The electric potential at the surface of an atomic nucleus (z = 50) of radius 9 × 10⁻¹³ cm is __________ × 10⁶ V. Numerical answer type. Work it out, then open the answer.

Answer: 8. Nucleus charge q = Ze = 50 × 1.6×10⁻¹⁹ = 8×10⁻¹⁸ C, radius R = 9×10⁻¹⁵ m V = kq/R = 9×10⁹ × 8×10⁻¹⁸9×10⁻¹⁵ V = 8×10⁶ V So the answer is 8.

The electric potential at the surface of an atomic nucleus (z = 50)… | JEE Main 2024 (27 Jan, Shift 2)

Q44JEE Main 2024 · 27 JAN · SHIFT 2Easy

Electric Potential & Equipotentials

The electric potential at the surface of an atomic nucleus $(z = 50)$ of radius $9 \times 10^{-13}\text{ cm}$ is __________ $\times 10^{6}\text{ V}$ .

Numerical answer type. Work it out, then open the answer.

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Answer: 8

Nucleus charge $q = Ze = 50 \times 1.6\times10^{-19} = 8\times10^{-18}\text{ C}$ , radius $R = 9\times10^{-15}\text{ m}$
$V = \frac{kq}{R} = \frac{9\times10^9 \times 8\times10^{-18}}{9\times10^{-15}}$
$V = 8\times10^{6}\text{ V}$
So the answer is 8.

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