The electric potential V at any point (x, y, z), all in metres in space is given by V = 4x2 volt. The electric field at the point (1, 0, 2) in volt/meter, is (a) 8 along negative X-axis (b) 8 along positive X-axis (c) 16 along negative X-axis (d) 16 along positive X-axis

Answer: (a). Ex = -(∂ V)/(∂ x) = -d/dx(4x²) = -8x At x = 1: Ex = -8 V/m; Ey = Ez = 0. So the answer is (a) 8 V/m along negative X-axis.

The electric potential V at any point (x, y, z), all in metres in… | NEET 2011 (AIPMT, Mains)

Q116NEET 2011 · AIPMT · MAINSEasy

Electric Potential & Equipotentials

The electric potential V at any point (x, y, z), all in metres in space is given by V = 4x2 volt. The electric field at the point (1, 0, 2) in volt/meter, is

Show answer and solution

Answer: (a)

$E_x = -\dfrac{\partial V}{\partial x} = -\dfrac{d}{dx}(4x^2) = -8x$
At $x = 1$ : $E_x = -8$ V/m; $E_y = E_z = 0$ .
So the answer is (a) 8 V/m along negative X-axis.

Report a mistake

Electric Potential & Equipotentials question from NEET 2011 (AIPMT, Mains)

More questions on Electric Potential & Equipotentials