The electron concentration in an n-type semiconductor is the same as hole concentration in a p-type semiconductor. An external field (electric) is applied across each of them. Compare the currents in them. (a) No current will flow in p-type, current will only flow in n-type (b) Current in n-type = current in p-type (c) current in p-type > current in n-type (d) current in n-type > current in p-type

Answer: (d). Current I = neAvd = neAμ E, so for equal carrier concentration and equal field, I ∝ μ. Electrons are more mobile than holes: μe > μh. So the answer is (d) current in n-type > current in p-type.

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Intrinsic & Extrinsic Semiconductors

The electron concentration in an n-type semiconductor is the same as hole concentration in a p-type semiconductor. An external field (electric) is applied across each of them. Compare the currents in them.

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Answer: (d)

Current $I = neAv_d = neA\mu E$ , so for equal carrier concentration and equal field, $I \propto \mu$ .
Electrons are more mobile than holes: $\mu_e > \mu_h$ .
So the answer is (d) current in n-type > current in p-type.

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