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NEET 2010 (AIPMT, Mains) · Photoelectric Effect: Einstein's Equation

Photoelectric Effect: Einstein's Equation question from NEET 2010 (AIPMT, Mains)

Q158NEET 2010 · AIPMT · MAINSMedium

Photoelectric Effect: Einstein's Equation

The electron in the hydrogen atom jumps from excited state (n = 3) to its ground state (n = 1) and the photons thus emitted irradiate a photosensitive material. If the work function of the material is 5.1 eV, the stopping potential is estimated to be (the energy of the electron in nth state En = −13.6n2 eV\frac{-13.6}{n^2}\text{ eV})

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Answer: (d)

  1. n=3→1n = 3 \to 1: E=13.6(1−19)=12.09E = 13.6\left(1 - \frac{1}{9}\right) = 12.09 eV.
  2. eV0=12.09−5.1≈7eV_0 = 12.09 - 5.1 \approx 7 eV
  3. So the answer is (d) 7 V.
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