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JEE Main 2022 (26 Jun, Shift 1) · Young's Modulus & Elongation

Young's Modulus & Elongation question from JEE Main 2022 (26 Jun, Shift 1)

Q20JEE Main 2022 · 26 JUN · SHIFT 1Easy

Young's Modulus & Elongation

The elongation of a wire on the surface of the earth is 10−4 m. The same wire of same dimensions is elongated by 6 ×\times 10−5 m on another planet. The acceleration due to gravity on the planet will be ____________ ms−2. (Take acceleration due to gravity on the surface of earth = 10 ms−2)

Numerical answer type. Work it out, then open the answer.

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Answer: 6

  1. Same wire and same mass: Δl=mgLAY∝g\Delta l = \frac{mgL}{AY} \propto g.
  2. g′=g×Δl′Δl=10×6×10−510−4g' = g \times \frac{\Delta l'}{\Delta l} = 10 \times \frac{6 \times 10^{-5}}{10^{-4}}
  3. g′=6 m s−2g' = 6\text{ m s}^{-2}
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