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MHT CET 2021 (22 Sep, Shift 2) · Thermal Radiation: Black Body, Stefan & Wien

Thermal Radiation: Black Body, Stefan & Wien question from MHT CET 2021 (22 Sep, Shift 2)

Q88MHT CET 2021 · 22 SEP · SHIFT 2Easy

Thermal Radiation: Black Body, Stefan & Wien

The emissive power of sphere of area 0.04 m20.04\text{ m}^{2} is 0.7 k cal s−1 m−20.7\text{ k cal s}^{-1}\text{ m}^{-2}. The amount of heat radiated in 20 second is

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Answer: (d)

  1. Heat radiated Q=E×A×tQ = E\times A\times t
  2. Q=0.7×0.04×20=0.56Q = 0.7\times0.04\times20 = 0.56 kcal
  3. So the answer is (d) 0.56 (the unit should be kcal; the unit printed in the options is wrong).
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