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JEE Main 2018 (16 Apr, Shift 1) · Organ Pipes & Resonance Tube

Organ Pipes & Resonance Tube question from JEE Main 2018 (16 Apr, Shift 1)

Q106JEE Main 2018 · 16 APR · SHIFT 1Easy

Organ Pipes & Resonance Tube

The end correction of a resonance column is 1 cm. If the shortest length resonating with the tuning fork is 10 cm, the next resonating length should be:

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Answer: (b)

First resonance: $l_1 + e = \frac{\lambda}{4} \Rightarrow 10 + 1 = 11\text{ cm}$ , so $\lambda = 44\text{ cm}$ .
Second resonance: $l_2 + e = \frac{3\lambda}{4} = 33\text{ cm}$
$l_2 = 33 - 1 = 32\text{ cm}$
So the answer is (b) 32 cm.

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