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JEE Main 2019 (9 Jan, Shift 2) · Energy Density & Intensity

Energy Density & Intensity question from JEE Main 2019 (9 Jan, Shift 2)

Q28JEE Main 2019 · 9 JAN · SHIFT 2Easy

Energy Density & Intensity

The energy associated with electric field is (UE) and with magnetic field is (UB) for an electromagnetic wave in free space. Then:

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Answer: (d)

  1. 12ε0E2=B22μ0\tfrac{1}{2}\varepsilon_0 E^2 = \dfrac{B^2}{2\mu_0} because E=cBE = cB and c2=1/(μ0ε0)c^2 = 1/(\mu_0\varepsilon_0).
  2. Energy is shared equally between the electric and magnetic fields.
  3. So the answer is (d) UE=UBU_E = U_B.
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