The energy density associated with electric field E and magnetic field B of an electromagnetic wave in free space is given by (ε₀ - permittivity of free space, μ₀ - permeability of free space) (a) UE = (ε₀ E²)/(2), UB = (B²)/(2μ₀) (b) UE = (E²)/(2ε₀), UB = (μ₀ B²)/(2) (c) UE = (ε₀ E²)/(2), UB = (μ₀ B²)/(2) (d) UE = (E²)/(2ε₀), UB = (B²)/(2μ₀)

Answer: (a). Electric energy density UE = 1/2ε₀ E² (same as in a capacitor). Magnetic energy density UB = (B²)/(2μ₀) (same as in an inductor). So the answer is (a).

The energy density associated with electric field E and magnetic… | JEE Main 2023 (6 Apr, Shift 2)

Q9JEE Main 2023 · 6 APR · SHIFT 2Easy

Energy Density & Intensity

The energy density associated with electric field $\vec{E}$ and magnetic field $\vec{B}$ of an electromagnetic wave in free space is given by $(\epsilon_0 -$ permittivity of free space, $\mu_0 -$ permeability of free space)

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Answer: (a)

Electric energy density $U_E = \tfrac{1}{2}\epsilon_0 E^2$ (same as in a capacitor).
Magnetic energy density $U_B = \dfrac{B^2}{2\mu_0}$ (same as in an inductor).
So the answer is (a).

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Energy Density & Intensity question from JEE Main 2023 (6 Apr, Shift 2)

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