The energy dissipated by a resistor is 10 mJ in 1 s when an electric current of 2 mA flows through it. The resistance is ___________ Ω. (Round off to the Nearest Integer) Numerical answer type. Work it out, then open the answer.

Answer: 2500. H = I² R t ⇒ R = (H)/(I² t). R = 10 × 10⁻³(2 × 10⁻³)² × 1 = 10⁻²4 × 10⁻⁶. R = 2500 Ω.

The energy dissipated by a resistor is 10 mJ in 1 s when an electric… | JEE Main 2021 (16 Mar, Shift 2)

Q31JEE Main 2021 · 16 MAR · SHIFT 2Easy

Electrical Power & Heating Effect

The energy dissipated by a resistor is 10 mJ in 1 s when an electric current of 2 mA flows through it. The resistance is ___________ $\Omega$ . (Round off to the Nearest Integer)

Numerical answer type. Work it out, then open the answer.

Show answer and solution

Answer: 2500

$H = I^2 R t \Rightarrow R = \frac{H}{I^2 t}$ .
$R = \frac{10 \times 10^{-3}}{(2 \times 10^{-3})^2 \times 1} = \frac{10^{-2}}{4 \times 10^{-6}}$ .
$R = 2500\ \Omega$ .

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