Physics Circle home Student Login

Home›Chapters›Dual Nature of Radiation and Matter PYQs›Photons: Energy, Momentum & Radiation Pressure›Question 42

NEET 2000 (AIPMT) · Photons: Energy, Momentum & Radiation Pressure

Photons: Energy, Momentum & Radiation Pressure question from NEET 2000 (AIPMT)

Q42NEET 2000 · AIPMTEasy

Photons: Energy, Momentum & Radiation Pressure

The energy of a photon of light is 3 eV3\text{ eV}. Then the wavelength of photon must be

Show answer and solution

Answer: (b)

  1. λ=hcE\lambda = \frac{hc}{E} with hc≈12375 eV A˚hc \approx 12375\text{ eV Å}.
  2. λ=123753 A˚=4125 A˚=412.5 nm\lambda = \frac{12375}{3}\text{ Å} = 4125\text{ Å} = 412.5\text{ nm}
  3. So the answer is (b) 412.5 nm412.5\text{ nm}.
Report a mistake

More questions on Photons: Energy, Momentum & Radiation Pressure