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MHT CET 2021 (23 Sep, Shift 1) · Bohr Model: Orbits, Speed & Angular Momentum

Bohr Model: Orbits, Speed & Angular Momentum question from MHT CET 2021 (23 Sep, Shift 1)

Q86MHT CET 2021 · 23 SEP · SHIFT 1Medium

Bohr Model: Orbits, Speed & Angular Momentum

The energy of an electron in the excited hydrogen atom is $-3.4\text{ eV}$ . Then according to Bohr's theory, the angular momentum of the electron in that excited state is ( $h =$ Plank's constant)

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Answer: (c)

$E_n = -\frac{13.6}{n^2}$ : $n^2 = \frac{13.6}{3.4} = 4$ , so $n = 2$ .
$L = \frac{2h}{2\pi} = \frac{h}{\pi}$
So the answer is (c) $\frac{h}{\pi}$ .

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