Nuclear Fission & Fusion question from JEE Main 2024 (9 Apr, Shift 2)

The energy released in the fusion of $2\text{ kg}$ of hydrogen deep in the sun is $E_{H}$ and the energy released in the fission of $2\text{ kg}$ of ${}^{235}\text{U}$ is $E_{U}$. The ratio $\frac{E_{H}}{E_{U}}$ is approximately: (Consider the fusion reaction as $4\,{}^{1}_{1}H + 2\text{e}^{-} \rightarrow {}^{4}_{2}\text{He} + 2v + 6\gamma + 26.7\text{ MeV}$, energy released in the fission reaction of ${}^{235}\text{U}$ is $200\text{ MeV}$ per fission nucleus and $\text{N}_{\text{A}} = 6.023 \times 10^{23})$