Physics Circle home Student Login

Home›Chapters›Atomic Structure PYQs›Energy of the Electron & Energy Levels›Question 43

JEE Main 2018 (15 Apr, Shift 1) · Energy of the Electron & Energy Levels

Energy of the Electron & Energy Levels question from JEE Main 2018 (15 Apr, Shift 1)

Q43JEE Main 2018 · 15 APR · SHIFT 1Medium

Energy of the Electron & Energy Levels

The energy required to remove the electron from a singly ionized Helium atom is 2.22.2 times the energies required to remove an electron from Helium atom. The total energy required to ionize the Helium atom completely is:

Show answer and solution

Answer: (c)

  1. Removing the electron from He+^+ (Z=2Z = 2, n=1n = 1): 13.6×4=54.413.6 \times 4 = 54.4 eV.
  2. First ionisation of He =54.42.2≈24.7= \frac{54.4}{2.2} \approx 24.7 eV.
  3. Total =54.4+24.7≈79= 54.4 + 24.7 \approx 79 eV
  4. So the answer is (c) 7979 eV.
Report a mistake

More questions on Energy of the Electron & Energy Levels