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JEE Main 2019 (9 Jan, Shift 2) · Satellite Energy & Weightlessness

Satellite Energy & Weightlessness question from JEE Main 2019 (9 Jan, Shift 2)

Q28JEE Main 2019 · 9 JAN · SHIFT 2Medium

Satellite Energy & Weightlessness

The energy required to take a satellite to a height 'h' above Earth surface (radius of Earth = 6.4 ×\times 103 km) is E1 and kinetic energy required for the satellite to be in a circular orbit at this height is E2. The value of h for which E1 and E2 are equal, is

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Answer: (b)

  1. E1=GMmhR(R+h)E_1 = \frac{GMmh}{R(R+h)} and E2=GMm2(R+h)E_2 = \frac{GMm}{2(R+h)}.
  2. E1=E2⇒hR=12⇒h=R2E_1 = E_2 \Rightarrow \frac{h}{R} = \frac{1}{2} \Rightarrow h = \frac{R}{2}.
  3. h=3.2×103h = 3.2\times10^3 km.
  4. So the answer is (b).
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