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JEE Main 2021 (20 Jul, Shift 1) · Applications of Dimensional Analysis

Applications of Dimensional Analysis question from JEE Main 2021 (20 Jul, Shift 1)

Q46JEE Main 2021 · 20 JUL · SHIFT 1Medium

Applications of Dimensional Analysis

The entropy of any system is given by

S=α2βln⁡[μkRJβ2+3]S = \alpha^2\beta\ln\left[\frac{\mu kR}{J\beta^2} + 3\right] where α\alpha and β\beta are the constants. μ\mu, J, k and R are no. of moles, mechanical equivalent of heat, Boltzmann constant and gas constant respectively.

[Take S=dQTS = \frac{dQ}{T} ]

Choose the incorrect option from the following:

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Answer: (d)

  1. The log argument is dimensionless and JJ (J/cal) is dimensionless, so [β2]=[μkR]=(J/K)2[\beta^2] = [\mu kR] = (\text{J/K})^2, giving [β]=[\beta] = J/K =[S]= [S].
  2. S=α2βS = \alpha^2\beta then makes α\alpha dimensionless.
  3. (a) α\alpha and JJ both dimensionless: correct. (b) SS has dimensions, α\alpha does not: correct. (c) S,β,k,μRS, \beta, k, \mu R are all J/K: correct.
  4. (d) kk has dimension J/K but α\alpha is dimensionless, so (d) is the incorrect option.
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