The equation λ = (1.227)/(x) nm can be used to find the de-Brogli wavelength of an electron. In this equation x stands for: Where m = mass of electron P = momentum of electron K = Kinetic energy of electron V = Accelerating potential in volts for electron (a) √(mK) (b) √(P) (c) √(K) (d) √(V)

Answer: (d). For an electron accelerated through V: λ = (h)/(√(2meV)) = (1.227)/(√(V)) nm. So x = √(V). So the answer is (d) √(V).

The equation λ = (1.227)/(x) nm can be used to find the de-Brogli… | JEE Main 2022 (28 Jul, Shift 1)

Q80JEE Main 2022 · 28 JUL · SHIFT 1Easy

Matter Waves: de Broglie Wavelength

The equation $\lambda = \frac{1.227}{x}\text{ nm}$ can be used to find the de-Brogli wavelength of an electron. In this equation $x$ stands for:

Where

$\mathrm{m} =$ mass of electron

$\mathrm{P} =$ momentum of electron

$\mathrm{K} =$ Kinetic energy of electron

$\mathrm{V} =$ Accelerating potential in volts for electron

Show answer and solution

Answer: (d)

For an electron accelerated through $V$ : $\lambda = \dfrac{h}{\sqrt{2meV}} = \dfrac{1.227}{\sqrt{V}}$ nm.
So $x = \sqrt{V}$ .
So the answer is (d) $\sqrt{V}$ .