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MHT CET 2026 (19 Apr, Shift 2) · Progressive Wave Equation

Progressive Wave Equation question from MHT CET 2026 (19 Apr, Shift 2)

Q9MHT CET 2026 · 19 APR · SHIFT 2Easy

Progressive Wave Equation

The equation of a progressive wave is given by $y = 6\cos(100t - 4x)$ where $y$ is in $\mu$ m, $x$ in metre and $t$ in second. The ratio of the maximum particle velocity to the velocity of wave is

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Answer: (c)

For $y = A\cos(\omega t - kx)$ : $v_{max} = A\omega$ and $v = \frac{\omega}{k}$ , so $\frac{v_{max}}{v} = Ak$ .
$A = 6\ \mu\text{m} = 6 \times 10^{-6}$ m, $k = 4\ \text{m}^{-1}$
$\frac{v_{max}}{v} = 6 \times 10^{-6} \times 4 = 2.4 \times 10^{-5}$
So the answer is (c) $2.4 \times 10^{-5}$ .

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