The equation of a stationary wave along a stretched string is y = 5sin (π x)/(3)cos 40π t where x and y are in cm and t in second. The separation between two adjacent nodes is (a) 6 cm (b) 4 cm (c) 3 cm (d) 1.5 cm

Answer: (c). k = π/3 = (2π)/(λ) ⇒ λ = 6 cm. Adjacent nodes are (λ)/(2) = 3 cm apart. So the answer is (c) 3 cm.

The equation of a stationary wave along a stretched string is y =… | MHT CET 2026 (14 May, Shift 2)

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Stationary Waves & Vibrating Strings

The equation of a stationary wave along a stretched string is $y = 5\sin\frac{\pi x}{3}\cos 40\pi t$ where $x$ and $y$ are in cm and $t$ in second. The separation between two adjacent nodes is

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Answer: (c)

$k = \frac{\pi}{3} = \frac{2\pi}{\lambda} \Rightarrow \lambda = 6\text{ cm}$ .
Adjacent nodes are $\frac{\lambda}{2} = 3\text{ cm}$ apart.
So the answer is (c) $3$ cm.

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