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JEE Main 2026 (2 Apr, Shift 2) · Periodic Motion & SHM Basics

Periodic Motion & SHM Basics question from JEE Main 2026 (2 Apr, Shift 2)

Q15JEE Main 2026 · 2 APR · SHIFT 2Medium

Periodic Motion & SHM Basics

The equation of motion of a particle is given by x=asin⁡(50t+π/3)x = a\sin(50t + \pi/3) cm. The particle will come to rest at time t1t_1 and it will have zero acceleration at time t2t_2. The t1t_1 and t2t_2 respectively are ________.

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Answer: (a)

  1. Rest at the extreme: 50t1+π3=π2⇒t1=π/650=π300 s50t_1 + \frac{\pi}{3} = \frac{\pi}{2} \Rightarrow t_1 = \frac{\pi/6}{50} = \frac{\pi}{300}\text{ s}
  2. Zero acceleration at x=0x = 0: 50t2+π3=π⇒t2=2π/350=π75 s50t_2 + \frac{\pi}{3} = \pi \Rightarrow t_2 = \frac{2\pi/3}{50} = \frac{\pi}{75}\text{ s}
  3. So the answer is (a).
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