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JEE Main 2024 (27 Jan, Shift 2) · Applications of Dimensional Analysis

Applications of Dimensional Analysis question from JEE Main 2024 (27 Jan, Shift 2)

Q25JEE Main 2024 · 27 JAN · SHIFT 2Medium

Applications of Dimensional Analysis

The equation of state of a real gas is given by (P+aV2)(V−b)=RT\left(\mathrm{P} + \frac{\mathrm{a}}{\mathrm{V}^2}\right)(\mathrm{V} - \mathrm{b}) = \mathrm{RT}, where P,V\mathrm{P, V} and T\mathrm{T} are pressure, volume and temperature respectively and R\mathrm{R} is the universal gas constant. The dimensions of ab2\frac{\mathrm{a}}{\mathrm{b}^2} is similar to that of:

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Answer: (a)

  1. Only like quantities add: aV2\dfrac{a}{V^2} has dimension of PP, so [a]=[PV2][a] = [PV^2].
  2. bb is subtracted from VV, so [b]=[V][b] = [V].
  3. [ab2]=PV2V2=[P]\left[\dfrac{a}{b^2}\right] = \dfrac{PV^2}{V^2} = [P].
  4. So the answer is (a) P.
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