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MHT CET 2025 (22 Apr, Shift 1) · Progressive Wave Equation

Progressive Wave Equation question from MHT CET 2025 (22 Apr, Shift 1)

Q29MHT CET 2025 · 22 APR · SHIFT 1Easy

Progressive Wave Equation

The equation of wave is y=60sin⁡(1200t−6x)y = 60\sin(1200t - 6x), where ' yy ' is in micron, ' tt ' is in second and ' xx ' is in metre. The ratio of maximum particle velocity to the wave velocity of wave propagation is

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Answer: (c)

  1. vmaxv=Aωω/k=Ak\frac{v_{max}}{v} = \frac{A\omega}{\omega/k} = Ak
  2. A=60 μm=6×10−5A = 60\ \mu\text{m} = 6 \times 10^{-5} m, k=6 m−1k = 6\ \text{m}^{-1}
  3. Ak=6×10−5×6=3.6×10−4Ak = 6 \times 10^{-5} \times 6 = 3.6 \times 10^{-4}
  4. So the answer is (c) 3.6×10−43.6 \times 10^{-4}.
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