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JEE Main 2022 (24 Jun, Shift 1) · Reflection, Superposition & Interference

Reflection, Superposition & Interference question from JEE Main 2022 (24 Jun, Shift 1)

Q15JEE Main 2022 · 24 JUN · SHIFT 1Medium

Reflection, Superposition & Interference

The equations of two waves are given by:

y1 = 5 sin 2 $\pi$ (x - vt) cm

y2 = 3 sin 2 $\pi$ (x $-$ vt + 1.5) cm

These waves are simultaneously passing through a string. The amplitude of the resulting wave is:

Show answer and solution

Answer: (a)

Phase difference $\phi = 2\pi \times 1.5 = 3\pi$ , i.e. the waves are in opposite phase.
$A_R = 5 - 3 = 2\text{ cm}$ .
So the answer is (a) $2\text{ cm}$ .

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