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MHT CET 2026 (18 Apr, Shift 2) · Combination of Inductors, LR & LC Circuits

Combination of Inductors, LR & LC Circuits question from MHT CET 2026 (18 Apr, Shift 2)

Q4MHT CET 2026 · 18 APR · SHIFT 2Medium

Combination of Inductors, LR & LC Circuits

The equivalent inductance between A and B is equal to

Figure

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Answer: (c)

  1. Let PP = junction after 1 H, QQ = junction after 3 H. The top wire joins AA to QQ; the bottom wire joins PP to BB.
  2. So Q≡AQ \equiv A, P≡BP \equiv B: 1 H (AA–PP), 2 H (PP–top), 3 H (PP–QQ) and 4 H (QQ–BB) all lie between AA and BB.
  3. 1L=1+12+13+14=2512\frac{1}{L} = 1 + \frac{1}{2} + \frac{1}{3} + \frac{1}{4} = \frac{25}{12}
  4. So the answer is (c) 1225 H\frac{12}{25}\text{ H}.
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