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NEET 2020 (Phase 2) · Combination of Resistors

Combination of Resistors question from NEET 2020 (Phase 2)

Q59NEET 2020 · PHASE 2Medium

Combination of Resistors

The equivalent resistance between AA and BB for the mesh shown in the figure is

Figure

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Answer: (c)

  1. The upper 4 Ω4\ \Omega and 8 Ω8\ \Omega meet at the apex, so they are in series: 12 Ω12\ \Omega.
  2. This 12 Ω12\ \Omega is in parallel with the 6 Ω6\ \Omega: 12×618=4 Ω\dfrac{12 \times 6}{18} = 4\ \Omega.
  3. In series with the lower 4 Ω4\ \Omega and 8 Ω8\ \Omega: RAB=4+4+8=16 ΩR_{AB} = 4 + 4 + 8 = 16\ \Omega.
  4. So the answer is (c) 16 Ω16\ \Omega.
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