Combination of Resistors question from JEE Main 2024 (9 Apr, Shift 1)

Answer: (c)

1. A goes to the $6\ \Omega$, B to the $8\ \Omega$. The vertical middle wire makes the top-middle and bottom-middle points one node X; the horizontal middle wire (it jumps over the vertical one) makes the two side midpoints one node Y.
2. Between X and Y: $10 + 5 = 15$, $7 + 8 = 15$ and $11 + 4 = 15\ \Omega$, all in parallel $= 5\ \Omega$.
3. $R_{AB} = 6 + 5 + 8 = 19\ \Omega$. So the answer is (c) $19\ \Omega$.