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MHT CET 2025 (23 Apr, Shift 1) · Wheatstone Bridge & Metre Bridge

Wheatstone Bridge & Metre Bridge question from MHT CET 2025 (23 Apr, Shift 1)

Q20MHT CET 2025 · 23 APR · SHIFT 1Medium

Wheatstone Bridge & Metre Bridge

The equivalent resistance of the following circuit when no current flows in the resistance of 5 Ω5\ \Omega is nearly

Figure

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Answer: (b)

  1. 1015=2030\dfrac{10}{15} = \dfrac{20}{30}, so the bridge is balanced and 5 Ω5\ \Omega carries no current.
  2. Path ABC: 10+15=25 Ω10 + 15 = 25\ \Omega; path ADC: 20+30=50 Ω20 + 30 = 50\ \Omega
  3. Req=25×5075=16.7≈17 ΩR_{eq} = \dfrac{25 \times 50}{75} = 16.7 \approx 17\ \Omega
  4. So the answer is (b) 17 Ω17\ \Omega.
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