The escape velocity for a body projected vertically upwards from the surface of earth is 11 km/s. If the body is projected at an angle of 45° with the vertical, the escape velocity will be (a) 11√(2) km/s (b) 22 km/s (c) 11 km/s (d) (11)/(√(2)) km/s

Answer: (c). Escape needs 1/2mv² ≥ GMm/R; energy is a scalar, so the direction of projection does not matter. Hence ve is the same at any angle: 11 km/s. So the answer is (c) 11 km/s.

The escape velocity for a body projected vertically upwards from the… | JEE Main 2003 (AIEEE)

Q77JEE Main 2003 · AIEEEEasy

Escape Velocity

The escape velocity for a body projected vertically upwards from the surface of earth is $11\text{ km/s}.$ If the body is projected at an angle of $45^\circ$ with the vertical, the escape velocity will be

Show answer and solution

Answer: (c)

Escape needs $\frac{1}{2}mv^2 \ge \frac{GMm}{R}$ ; energy is a scalar, so the direction of projection does not matter.
Hence $v_e$ is the same at any angle: $11\text{ km/s}$ .
So the answer is (c) $11\text{ km/s}$ .

Report a mistake

Escape Velocity question from JEE Main 2003 (AIEEE)

More questions on Escape Velocity