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MHT CET 2020 (19 Oct, Shift 2) · Escape Velocity

Escape Velocity question from MHT CET 2020 (19 Oct, Shift 2)

Q55MHT CET 2020 · 19 OCT · SHIFT 2Easy

Escape Velocity

The escape velocity of a body from any planet, whose mass is six times the mass of earth and radius is twice the radius of earth will (v ${}_e$ = escape velocity of a body from the earth's surface)

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Answer: (d)

$v_e \propto \sqrt{\frac{M}{R}}$
$\frac{v_p}{v_e} = \sqrt{\frac{6}{2}} = \sqrt{3}$
So the answer is (d) $\sqrt{3}v_e$ .

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