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MHT CET 2019 (2 May, Shift 2) · Excess Pressure: Drops & Bubbles

Excess Pressure: Drops & Bubbles question from MHT CET 2019 (2 May, Shift 2)

Q53MHT CET 2019 · 2 MAY · SHIFT 2Easy

Excess Pressure: Drops & Bubbles

The excess of pressure, due to surface tension, on a spherical liquid drop of radius ' RR ' is proportional to

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Answer: (a)

  1. Excess pressure in a drop ΔP=2TR\Delta P = \frac{2T}{R}.
  2. So ΔP∝R−1\Delta P \propto R^{-1}.
  3. So the answer is (a) R−1R^{-1}.
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