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JEE Main 2025 (3 Apr, Shift 2) · Excess Pressure: Drops & Bubbles

Excess Pressure: Drops & Bubbles question from JEE Main 2025 (3 Apr, Shift 2)

Q21JEE Main 2025 · 3 APR · SHIFT 2Medium

Excess Pressure: Drops & Bubbles

The excess pressure inside a soap bubble A in air is half the excess pressure inside another soap bubble B in air. If the volume of the bubble A is nn times the volume of the bubble BB, then, the value of nn is__________.

Numerical answer type. Work it out, then open the answer.

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Answer: 8

  1. Excess pressure P=4Tr∝1rP = \frac{4T}{r} \propto \frac{1}{r}.
  2. PA=PB2⇒rA=2rBP_A = \frac{P_B}{2} \Rightarrow r_A = 2r_B
  3. VAVB=(rArB)3=8\frac{V_A}{V_B} = \left(\frac{r_A}{r_B}\right)^3 = 8
  4. n=8n = 8
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