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MHT CET 2025 (22 Apr, Shift 2) · Excess Pressure: Drops & Bubbles

Excess Pressure: Drops & Bubbles question from MHT CET 2025 (22 Apr, Shift 2)

Q17MHT CET 2025 · 22 APR · SHIFT 2Medium

Excess Pressure: Drops & Bubbles

The excess pressure inside a soap bubble is 1.5 times the excess pressure inside a second soap bubble. The volume of the second bubble is ' $x$ ' times the volume of the first bubble. The value of ' x ' is

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Answer: (d)

$\Delta P \propto \frac{1}{R}$ ; $\Delta P_1 = 1.5\,\Delta P_2 \Rightarrow R_2 = 1.5\,R_1 = \frac{3}{2}R_1$ .
$x = \frac{V_2}{V_1} = \left(\frac{3}{2}\right)^3 = \frac{27}{8}$
So the answer is (d) $\frac{27}{8}$ .

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