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JEE Main 2024 (9 Apr, Shift 2) · Excess Pressure: Drops & Bubbles

Excess Pressure: Drops & Bubbles question from JEE Main 2024 (9 Apr, Shift 2)

Q25JEE Main 2024 · 9 APR · SHIFT 2Easy

Excess Pressure: Drops & Bubbles

The excess pressure inside a soap bubble is thrice the excess pressure inside a second soap bubble. The ratio between the volume of the first and the second bubble is:

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Answer: (b)

$\Delta P = \frac{4T}{R} \propto \frac{1}{R}$ ; $\Delta P_1 = 3\Delta P_2 \Rightarrow R_1 = \frac{R_2}{3}$ .
$\frac{V_1}{V_2} = \left(\frac{R_1}{R_2}\right)^3 = \frac{1}{27}$
So the answer is (b) $1 : 27$ .

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