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MHT CET 2026 (14 May, Shift 2) · Excess Pressure: Drops & Bubbles

Excess Pressure: Drops & Bubbles question from MHT CET 2026 (14 May, Shift 2)

Q6MHT CET 2026 · 14 MAY · SHIFT 2Medium

Excess Pressure: Drops & Bubbles

The excess pressure inside a spherical drop of water is four times that of another drop. Then, their respective mass ratio is

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Answer: (d)

  1. ΔP=2Tr∝1r\Delta P = \frac{2T}{r} \propto \frac{1}{r}; ΔP1=4ΔP2⇒r1=r24\Delta P_1 = 4\Delta P_2 \Rightarrow r_1 = \frac{r_2}{4}.
  2. Mass ∝\propto volume ∝r3\propto r^3: m1m2=(14)3=164\frac{m_1}{m_2} = \left(\frac{1}{4}\right)^3 = \frac{1}{64}
  3. So the answer is (d) 1:641 : 64.
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