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MHT CET 2026 (17 Apr, Shift 1) · Excess Pressure: Drops & Bubbles

Excess Pressure: Drops & Bubbles question from MHT CET 2026 (17 Apr, Shift 1)

Q10MHT CET 2026 · 17 APR · SHIFT 1Medium

Excess Pressure: Drops & Bubbles

The excess pressure inside a spherical water drop A is four times that of another water drop B. Then, the ratio of the mass of water drop A to that of drop B is

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Answer: (d)

  1. ΔP=2Tr∝1r\Delta P = \frac{2T}{r} \propto \frac{1}{r}; ΔPA=4ΔPB⇒rA=rB4\Delta P_A = 4\Delta P_B \Rightarrow r_A = \frac{r_B}{4}.
  2. mAmB=(rArB)3=164\frac{m_A}{m_B} = \left(\frac{r_A}{r_B}\right)^3 = \frac{1}{64}
  3. So the answer is (d) 1:641 : 64.
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