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MHT CET 2026 (15 Apr, Shift 2) · Excess Pressure: Drops & Bubbles

Excess Pressure: Drops & Bubbles question from MHT CET 2026 (15 Apr, Shift 2)

Q11MHT CET 2026 · 15 APR · SHIFT 2Medium

Excess Pressure: Drops & Bubbles

The excess pressure inside the first soap bubble of radius $R_1$ is three times that inside the second soap bubble of radius $R_2$ . The ratio of volumes of the first to second bubble is

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Answer: (a)

$\Delta P = \frac{4T}{R} \propto \frac{1}{R}$ ; $\Delta P_1 = 3\Delta P_2 \Rightarrow R_1 = \frac{R_2}{3}$ .
$\frac{V_1}{V_2} = \left(\frac{R_1}{R_2}\right)^3 = \frac{1}{27}$
So the answer is (a) $1 : 27$ .

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