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JEE Main 2005 (AIEEE) · Heat Conduction

Heat Conduction question from JEE Main 2005 (AIEEE)

Q53JEE Main 2005 · AIEEEMedium

Heat Conduction

The figure shows a system of two concentric spheres of radii r1r_1 and r2r_2 are kept at temperatures T1T_1 and T2T_2, respectively. The radial rate of flow of heat in a substance between the two concentric spheres is proportional to

Figure

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Answer: (d)

  1. A thin shell of radius rr and thickness drdr: H=−K(4πr2)dTdrH = -K(4\pi r^2)\dfrac{dT}{dr}, same HH through every shell.
  2. H∫r1r2drr2=4πK(T1−T2)⇒H(1r1−1r2)=4πK(T1−T2)H\int_{r_1}^{r_2}\dfrac{dr}{r^2} = 4\pi K(T_1-T_2) \Rightarrow H\left(\dfrac{1}{r_1}-\dfrac{1}{r_2}\right) = 4\pi K(T_1-T_2)
  3. H=4πKr1r2(T1−T2)r2−r1H = \dfrac{4\pi K r_1 r_2 (T_1-T_2)}{r_2-r_1}
  4. So the answer is (d) H∝r1r2r2−r1H \propto \dfrac{r_1 r_2}{r_2-r_1}.
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