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NEET 2009 (AIPMT) · Kepler's Laws & Planetary Motion

Kepler's Laws & Planetary Motion question from NEET 2009 (AIPMT)

Q28NEET 2009 · AIPMTEasy

Kepler's Laws & Planetary Motion

The figure shows elliptical orbit of a planet m about the sun S. The shaded area SCD is twice the shaded area SAB. If t1 is the time for the planet to move from C to D and t2 is the time to move from A to B then

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Answer: (b)

Kepler's second law: areal velocity is constant, so time $\propto$ area swept.
Area SCD $= 2\times$ area SAB $\Rightarrow t_1 = 2t_2$ .
So the answer is (b) $t_1 = 2t_2$ .

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