Photoelectric Experiment: Intensity, Stopping Potential & Graphs question from MHT CET 2024 (9 May, Shift 2)

Answer: (b)

1. Stopping potential $V_0 = (h\nu - \phi)/e$ increases with frequency for the same metal.
2. From the graph, the stopping potentials are in the order $V_0^1 < V_0^2 < V_0^3 < V_0^4$ for curves $a, b, c, d$.
3. All curves have the same saturation current, so only the frequency differs.
4. So $f_a < f_b < f_c < f_d$: the answer is (b).