The figure shows two masses ' m ' and ' M ' connected by a light… | MHT CET 2025 (23 Apr, Shift 1)

Q6MHT CET 2025 · 23 APR · SHIFT 1Medium

Centripetal Acceleration & Force

The figure shows two masses ' $m$ ' and ' $M$ ' connected by a light string that passes through $\text{a}$ small hole ' $O$ ' at the centre of the table. Mass ' $m$ ' is moved round in a horizontal circle with ' $O$ ' as the centre. The frequency with which ' $m$ ' should be revolved so that ' $M$ ' remains stationary is ( $g =$ gravitational acceleration)

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Answer: (b)

M stays at rest, so string tension $T = Mg$ .
The same tension gives the centripetal force on m: $Mg = m\omega^2 L$ .
$\omega = \sqrt{\frac{Mg}{mL}}$ , and $f = \frac{\omega}{2\pi}$ .
So the answer is (b) $\frac{1}{2\pi}\sqrt{\frac{Mg}{mL}}$ .

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