Physics Circle home Student Login

Home›Chapters›Wave Motion PYQs›Organ Pipes & Resonance Tube›Question 76

JEE Main 2022 (25 Jun, Shift 1) · Organ Pipes & Resonance Tube

Organ Pipes & Resonance Tube question from JEE Main 2022 (25 Jun, Shift 1)

Q76JEE Main 2022 · 25 JUN · SHIFT 1Easy

Organ Pipes & Resonance Tube

The first overtone frequency of an open organ pipe is equal to the fundamental frequency of a closed organ pipe. If the length of the closed organ pipe is 20 cm, the length of the open organ pipe is _____________ cm.

Numerical answer type. Work it out, then open the answer.

Show answer and solution

Answer: 80

  1. First overtone of open pipe: vLo\frac{v}{L_o}. Closed fundamental: v4Lc\frac{v}{4L_c}.
  2. vLo=v4Lc⇒Lo=4Lc=4×20\frac{v}{L_o}=\frac{v}{4L_c} \Rightarrow L_o=4L_c=4\times20
  3. Lo=80 cmL_o=80\text{ cm}
Report a mistake

More questions on Organ Pipes & Resonance Tube