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JEE Main 2013 (22 Apr, Shift 1) · Optical Instruments & the Eye

Optical Instruments & the Eye question from JEE Main 2013 (22 Apr, Shift 1)

Q48JEE Main 2013 · 22 APR · SHIFT 1Difficult

Optical Instruments & the Eye

The focal length of the objective and the eyepiece of a telescope are 50 cm and 5 cm respectively. If the telescope is focussed for distinct vision on a scale distant 2 m from its objective, then its magnifying power will be:

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Answer: (d)

  1. Objective: 1vo=150−1200=3200⇒vo=2003\dfrac{1}{v_o} = \dfrac{1}{50} - \dfrac{1}{200} = \dfrac{3}{200} \Rightarrow v_o = \dfrac{200}{3} cm, mo=−vouo=−13m_o = -\dfrac{v_o}{u_o} = -\dfrac{1}{3}.
  2. Eyepiece with image at D=25D = 25 cm: me=1+Dfe=1+255=6m_e = 1 + \dfrac{D}{f_e} = 1 + \dfrac{25}{5} = 6.
  3. M=mome=−13×6=−2M = m_o m_e = -\dfrac{1}{3} \times 6 = -2.
  4. So the answer is (d) −2-2.
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