The following figure represents two biconvex lenses L₁ and L₂ having focal length 10 cm and 15 cm respectively. The distance between L₁ & L₂ is: (a) 25 cm (b) 35 cm (c) 10 cm (d) 15 cm

Answer: (a). A ray parallel to the axis enters and leaves parallel, so the focus of L₁ coincides with the focus of L₂ (the ray crosses the axis there). d = f₁ + f₂ = 10 + 15 = 25 cm So the answer is (a) 25 cm.

The following figure represents two biconvex lenses L₁ and L₂ having… | JEE Main 2024 (9 Apr, Shift 2)

Q29JEE Main 2024 · 9 APR · SHIFT 2Medium

Combination of Lenses

The following figure represents two biconvex lenses $L_1$ and $L_2$ having focal length $10\text{ cm}$ and $15\text{ cm}$ respectively. The distance between $L_1$ & $L_2$ is:

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Answer: (a)

A ray parallel to the axis enters and leaves parallel, so the focus of $L_1$ coincides with the focus of $L_2$ (the ray crosses the axis there).
$d = f_1 + f_2 = 10 + 15 = 25\text{ cm}$
So the answer is (a) 25 cm.

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Combination of Lenses question from JEE Main 2024 (9 Apr, Shift 2)

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