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MHT CET 2025 (20 Apr, Shift 2) · Thermal Radiation: Black Body, Stefan & Wien

Thermal Radiation: Black Body, Stefan & Wien question from MHT CET 2025 (20 Apr, Shift 2)

Q45MHT CET 2025 · 20 APR · SHIFT 2Easy

Thermal Radiation: Black Body, Stefan & Wien

The following graph represents the radiant power versus wavelength of the black body. The area under the curve represents

Figure

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Answer: (d)

  1. The y-axis is energy emitted per unit time per unit area per unit wavelength, EλE_\lambda.
  2. Area under the curve =∫Eλ dλ= \int E_\lambda\, d\lambda adds this over all wavelengths.
  3. This is the total energy emitted per unit time per unit area, E=σT4E = \sigma T^4.
  4. So the answer is (d).
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